Question

What is the equation of the line that contains the point (6-1) and is perpendicular to line whose equation is y=2x+1

A(9,5)
B(-3,1)
C(6,3)
D(-9,7)

Answer 1

y = -x/2 + 2

what are those mutli choice answers?

if that point is (6,1)

y = -x/2 + 4

Explanation:

the perpendicular line has a gradient which is the negative inverse, that is -1/m

so the equation will be of the form y = -x/2 + c

substituting in the point (6, -1)

-1 = -6/2 + c

c = 2

so y = -x/2 + 2