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What is the equation of the line that is parallel to the line 5x + 2y = 12 and passes through the point (−2, 4)?

1 Answer

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Answer:

y=-2.5x+9

Explanation:

hey there

Ok so first you need to rearrange the equation 5x+2y=12 into the form y=mx+c with m being the gradient as in a parallel line the gradients are the same.

1) 5x+2y=12

2y=-5x+12

y=-2.5x+6

Next, we know that the gradient is -2.5 so using the information from the coordinates (-2,4) we are going to incorporate everything we know so far into the equation y=mx+c in hope of finding the y intercept (c)

2) we know y=4, x=-2, and m=2.5 so I'm going to substitute it into y=mx+x:

4=(-2.5*2)+c

4=(-5)+c

c=4+5

c=-9

y=-2.5x+9

hope this helped :)

User Cacsar
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