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the vertex of a parabola is located at (-2,5). If the parabola has a y-intercept of -27, which quadratic function represents the parabola in standard form? y=a(x-p)^2 +q

User Ecarrion
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1 Answer

1 vote

Answer:

f(x) = -8(x + 2)² + 5

Explanation:

y = a(x - p)² + q - the vertex form of an equation of a parabola with a vertex (p, q)

(-2, 5) ⇒ p = -2, q = 5

y = a(x + 2)² + 5 - the vertex form of an equation of the parabola with vertex (-2, 5)

y-intercept of -27 means x=0, y=-27

-27 = a(0 + 2)² + 5

-27 -5 = a(2)² + 5 -5

-32 = 4a

a = -8

The equation of the parabola in vertex form that has a vertex (-2, 5) and y-intercept of -27:

f(x) = -8(x + 2)² + 5

User Alex Ciocan
by
6.2k points
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