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Find three consecutive even numbers such that five times the smallest number is equal to twice the sum of the other two number

User Dantebarba
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6 votes

Answer:

let the integers be n, n+2 and n+4

5(n+4) = 2(n + n+2) +42

5n +20 = 4n +4+42

n = 46 -20 = 26

Explanation:

I think

User Nhat
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