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How many moles of hydrochloric acid are needed to react with 0.64 moles of potassium permanganate?

1 Answer

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Answer:

5.12 moles of hydrochloric acid.

Step-by-step explanation:

The balanced equation is:

2KMnO4 + 16HCl ---> 2KCL + 2MnCl2 + 5Cl2 + 8H2O

So 2 moles of potassium permanganate reacts with 16 moles of HCl.

So 0.64 moles KMnO4 react with (16/2) * 0.64

= 5.12 moles.

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