Question

A spring has a potential energy of 22.14 J and a mass of 5.7 kg. How far has it been stretched?

Answer 1

Far has it been stretched(x) = 0.80 meter (Approx)

Step-by-step explanation:

Given:

Mass = 5.7 kg

Potential energy = 22.14 J

Find:

Far has it been stretched(x)

Computation:

Force f = mg

Force f = (5.7)(9.8)

Force f = 55.86 N

Potential energy = 1/2(f)(x)

22.14 = 1/2(55.86)(x)

x = 0.7927 meter

Far has it been stretched(x) = 0.80 meter (Approx)