Answer:
![g=1.81\ m/s^2](https://img.qammunity.org/2021/formulas/physics/college/c97edt0g9ogrkqkp9nzagu2pe841y1q8iv.png)
Step-by-step explanation:
Mass of Jupiter's moon,
![M=8.94* 10^(22)\ kg](https://img.qammunity.org/2021/formulas/physics/college/ozngcioo9p14fdp4bbx7x7f30yip53i68c.png)
Radius, R = 1815 km
We need to find the acceleration due to gravity on the surface of Juptiter's moon. The formula for the acceleration due to gravity is given by :
![g=(GM)/(R^2)](https://img.qammunity.org/2021/formulas/physics/high-school/to4u8jsvijg0aeua63jz6cw1vb8cjy4to7.png)
G is universal gravitational constant
![g=(6.67* 10^(-11)* 8.94* 10^(22))/((1815* 10^3)^2)\\\\g=1.81\ m/s^2](https://img.qammunity.org/2021/formulas/physics/college/j8zekq24ckwo3ri8a4lxwb1obzotizrjsf.png)
So, the acceleration due to gravity on the Jupiter's moon is
.