Question

A cannon is fired horizontally from the edge of a small cliff. The height of the cliff is 104.0 m. The cannon ball is fired with a perfectly horizontal velocity of 24.6 m/s and it took 2.3s to reach the ground. How far will the cannon ball fly horizontally before it strikes the ground?

Answer 1

h = 134.65 m

Step-by-step explanation:

It is given that,

The height of the cliff is 104.0 m, h₀ = 104 m

Initial horizontal velocity of the ball, u = 24.6 m/s

It takes 2.3 s to reach the ground, t = 2.3 s

We need to find how far will the cannon ball fly horizontally before it strikes the ground. let it is h. Using second equation of motion as follows :

`h=h_0+ut+(1)/(2)at^2`

Here, a = -g

So,

`h=h_0+ut-(1)/(2)gt^2\\\\h=104+24.6(2.3)-(1)/(2)* 9.8* (2.3)^2\\\\h=134.65\ m`

So, the cannonball will cover a distance of 134.65 m before it strikes the ground.