Answer:
temperatur akhir = 444.5645⁰F
kerja = 31.353 Btu
Step-by-step explanation:
Sebuah Tangki yang kokoh terinsulasi mempunyai
T₁ = 212°F , V₁ = 10ft³
ц₁ = 26.782ft³/lbm , U₁ = 1077.4Btu/lbm
keadaan akhir:
P₂ = 20Psi , ц₂ = ц₁ = 26.782ft³/lbm
At P₂ = 20Psi
T ц U
440 26.644 1159.7
T₂ 26.782 U₂
500 28.458 1181.6
By interpolation T₂ = 444.5645⁰F
U₂ = 1161.366Btu/lbm
m = v₁ / ц₁
= 10 / 26,782
= 0.3734 lbm
kerja = m(U₂-U₁)
= 0.3734 ( 1161.366 - 1077.4 )
= 31.353 Btu