Answer:
The answer is "No since one triangle's hypotenuse is equivalent in length to the triangle's leg".
Step-by-step explanation:
When its corresponding sides are congruent, there may be two triangles. Here a leg of the ΔXYZ measurements 10 (XY = 10). So, it must calculate upwards of 10 on its hypotenuse (the biggest hand in a rectangle hand).
- The two triangle hypotenuse is different: hypotenuse ΔJKL the measures of the hypotenuse are hypotenuse of = (KL=10).
- The hypotenuse of ΔXYZ the measures of the hypotenuse is greater than ten (YZ>10), that's why it's not compatible and the triangles were not compatible.