Question

The sum of the measures of the angles of all triangles is 180°. If one angle of the triangle measures 45°, and the other two angles are equal, what is the measure of each of the other two angles? Please hurry, This question is on a timed test and I have 30 minutes left.

Answer 1

`\alpha = 67.5`

Explanation:

Represent the first angle with
`\theta`

`\theta = 45`

Represent the equal angles with
`\alpha`

So:

`\alpha + \alpha + \theta = 180`

Substitute 45 for
`\theta`

`\alpha + \alpha + 45 = 180`

Subtract 45 from both sides

`\alpha + \alpha + 45 - 45= 180 - 45`

`\alpha + \alpha = 135`

`2\alpha = 135`

Divide both sides by 2

`\alpha = 135/2`

`\alpha = 67.5`

Hence:

The measure of the other angles is 67.5