Question

If the ac peak current through a 100 ohm resistor is 1.7 A, the average power dissipated by the resistance is

Answer 1

The average power dissipated by the resistance is 144.5 W.

Step-by-step explanation:

Given;

peak current of the AC = I₀ = 1.7 A

resistance, R = 100 ohm

The root mean square current is given by;

`I_(rms) = 0.7071 \ I_o\\\\I_(rms) = 0.7071 * 1.7\\\\I_(rms) = 1.2021 \ A`

The average power dissipated by the resistance is given by;

`P_(avg) = I_(rms)^2R\\\\P_(avg) = (1.2021)^2(100)\\\\P_(avg) =144.5 \ W`

Therefore, the average power dissipated by the resistance is 144.5 W.