Question

A baseball is dropped from the top of the Eiffel tower. What is the velocity of the ball after it has dropped 256 ft

Answer 1

Velocity = 39.11 m/s

Step-by-step explanation:

Applying the third equation of motion:

`V^(2)` =
`U^(2)` + 2gh

where V is the final velocity of the baseball, U is its initial velocity, g is the force of gravity and h is the height.

Thus, U = 0, g = 9.8 m/
`s^(2)` and h = 256 ft

But, 1 ft = 0.3048 m

So that;

h = 256 feet = 78.0288 meters

`V^(2)` = 2 x 9.8 x 78.0288

=
`√(1529.37)`

V = 39.11 m/s

The velocity of the baseball is 39.11 m/s.