Answer:
Hello the diagram is missing attached below is the missing diagram
answer : The magnitude of the force = 746.27 N
Step-by-step explanation:
C to be Cx = 50 N
First we have to consider the equilibrium force in the all directions
In x direction
∑ Fx = 0
Fcos60 cos30 - Ax - Cx = 0
hence Ax = 0.433F - 50 ------- (1)
In y direction
∑ Fy = 0
F cos60 sin30 - By - Cy = 0
By + Cy = 0.25 F --------- (2)
In z direction
∑ Fz = 0
-Fsin60 + Az + Bz = 0
Az + Bz = 0.866 F --------- ( 3 )
Next we consider the equilibrium moments in all directions
In x direction
∑ Mx = 0
Cy(2) - Az(2) = 0
therefore; Cy - Az = 0 ----------- (4)
In y direction
∑ My = 0
Bz (1) - Cx(2) = 0
Bz (1 ) - 50(2) = 0
therefore Bz = 100 N --------------- (5)
In Z direction
∑ Mz = 0
-Ax(2) + By(1) + Cy ( 1.75 ) = 0 ---------- (6)
after solving each equation
Ax = -373.13 N
Az = -746.27 N
By = 559.70 N
Bz = 100 N
Cy = - 746.27 N
and F = -746.27 N