Answer:
67% or 0.67
Explanation:
Given that:
P(1 child under age 21) = 55%
P(2 children under age 21) = 22%
P(3 children under age 21) = 15%
P(4 children under age 21) = 5%
P(5 or more children under age 21) = 3%
If a family is selected at random, what is the probability the family has 1 or 3 children under the age of 21?
P(1 or 3 children under age 21):
Either the selected family has 1 child under 21 years of age OR the selected family has 3 children under 21 years of age ;
P(1 child under age 21) + P(3 children under age 21)
= 55% + 15%
= 67% = 0.67