Answer:
The acceleration of the motorbike as it came to a stop was -8.78 m/s² (NOTE: Negative sign indicates deceleration)
Step-by-step explanation:
From the question,
A motorbike is traveling to the left with a speed of 27.0 m/s.
This is the initial speed, that is, initial speed = 27.0 m/s
Also, from the question,
The rider slams on the brakes and the bike skids 41.5 m, that is, the bike covers a distance of 41.5 m after the rider slams on the brakes.
Distance = 41.5 m
To determine the acceleration of the motorbike as it came to a stop,
Since, the bike came to a stop, then, the final speed is 0 m/s
From one of the equations of motion for linear motion
v² = u² + 2as
Where v is the final speed (velocity)
u is the initial speed (velocity)
a is the acceleration
and s is the distance
From the question
v = 0 m/s
u = 27.0 m/s
s = 41.5 m
Putting these into the equation
v² = u² + 2as
0² = 27.0² + (2×a×41.5)
0 = 729.0 + 83a
83a = -729.0
a = -729.0 / 83
a = -8.78 m/s² (NOTE: Negative sign indicates deceleration)