Question

You push a 23 kg chair horizontal along the floor and it accelerates at 0.53 m/s2. If the coefficient of kinetic friction between the chair and the floor is 0.35, calculate the magnitude of your force.

Answer 1

F = 91.08 N

Step-by-step explanation:

It is given that,

Mass of a chair, m = 23 kg

Acceleration of the chair, a = 0.53 m/s²

The coefficient of kinetic friction between the chair and the floor is 0.35

We need to find the magnitude of the applied force. Let f is the frictional force and F is the applied force. We can use the equation of motion as follows :

F-f=ma

Also,
`f=\mu mg`

So,

`F-\mu mg=ma\\\\F=m(a+\mu g)\\\\\text{Putting all the values to find F}\\\\F=23* (0.53+0.35* 9.8)\\\\F=91.08\ N`

So, the magnitude of the applied force is 91.08 N.