Answer:
5 permanent operators and 7 temporary operators
Step-by-step explanation:
Let x represent the number of permanent operators and y represent the number of temporary operators.
The objective function is given as:
Minimize cost = 150x + 100y
There are 11 computer stations, hence:
x + y = 11 (1)
Also since the company averages at least 800 orders per day:
90x + 60y ≥ 800 (2)
The solution to the problem gives (11,0), (13.33, 0), (4.67, 6.33)
At (11, 0), Minimize cost = 150(11) + 100(0) = $1650
At (13.33, 0) , Minimize cost = 150(14) + 100(0) = $2000
At (4.67, 6.33), Minimize cost = 150(4.67) + 100(6.33) = $1334
The minimum cost is at x = 4.67 ≈ 5 and y = 6.33 ≈ 7
To minimize cost there is need to have 5 permanent operators and 7 temporary operators