Answer:
width of the pool = 50ft²
Area of the concrete pad = 1000ft²
Area of pool = 4000ft²
Explanation:
The question is incomplete. Find the complete question in the comment section.
Area of the pool and concrete pad = Length × Width
A = LW ..... 1
If you've determined that the length of the rectangular kids pool must be 30 feet greater than the width, then;
L = 30+W ..... 2
Substitute 2 into 1:
A = (30+W)W
A = W²+30W
Given Total area of concrete pad and pool = 5000ft²
Area of concrete pad+area of pool = 5000
(LW)pool + (LW)concrete pad = 5000
(30+W)W + 20W = 5000 (note that the width are the same (for the concrete and the pool)
W²+30W+20W = 5000
W²+50W-5000 = 0
W²+100W-50W-5000 = 0
W(W+100)-50(W+100) = 50
(W+100)(W-50)=0
W-50 = 0 and W+100 = 0
W= 50 and W = -100
Since width cannot be negative, hence the width of the pool that aligns with the concrete pad is 50feet.
Next is get the area of the concrete pad:
Area of concrete pad = 20w
Area of concrete pad = 20(50)
Area of concrete pad = 1000ft²
Get the area of the pool
Area of concrete pad+area of pool = 5000
1000+area of pool = 5000
Area of pool = 5000-1000
Area of pool = 4000ft²