![47 = 2(x + 3) + 3(x - 3)](https://img.qammunity.org/2021/formulas/mathematics/high-school/hp15xwa1rp19uonar5sst957ix91vdq92g.png)
![47 = 2x + 6 + 3x + - 9](https://img.qammunity.org/2021/formulas/mathematics/high-school/23f3joph34cja4f1ww2tuw7wdplf1la9bk.png)
![47 =(2 x + 3x) + (6 + - 9)](https://img.qammunity.org/2021/formulas/mathematics/high-school/zhtz1q5li6py5im1t8x8f9t6k9qyknvyuw.png)
![47 = 5x + - 3](https://img.qammunity.org/2021/formulas/mathematics/high-school/y1o5yolie9atd4d4e043hmtmdfy21akjqc.png)
![47 = 5x - 3](https://img.qammunity.org/2021/formulas/mathematics/high-school/wn4ktr0b7zqscu7jatvncgt5dl2cd0r18o.png)
![5x - 3 = 47](https://img.qammunity.org/2021/formulas/mathematics/high-school/kmf3lkrudhzb44e97z7p05ddil1hkhcw7e.png)
![5x = 47 + 3](https://img.qammunity.org/2021/formulas/mathematics/high-school/qp38u659yywd4e7kbgbef848p0joba0p11.png)
![5x = 50](https://img.qammunity.org/2021/formulas/mathematics/high-school/rixd1tkv698qdiut2xotk175zzf7vikd6n.png)
![x = (50)/(10)](https://img.qammunity.org/2021/formulas/mathematics/high-school/bv4oind4zzu6sztl1owno05099n2rb2q4t.png)
![x = 10](https://img.qammunity.org/2021/formulas/mathematics/middle-school/gwot6ylqcy58ja7tb07muh9lk3ac30atr9.png)
Let us check whether or not we have found out the correct value of x by placing 10 in the place of x .
So :-
![47 = 2(10 + 3) + 3(10 - 3)](https://img.qammunity.org/2021/formulas/mathematics/high-school/z76ggv5xez5tkdi7fwl9i4kxabu6ry4gn4.png)
![47 = (20 + 6) + (30 - 9)](https://img.qammunity.org/2021/formulas/mathematics/high-school/6xumbr0nfyhdfpsltxfv0qeqchlm5ds62d.png)
![47 = 26 + 21](https://img.qammunity.org/2021/formulas/mathematics/high-school/7klozpbeuzbec1dfwp71kiqvqq3irupd32.png)
![47 = 47](https://img.qammunity.org/2021/formulas/mathematics/high-school/61ps6vhuvbz8wuvw8z7hr91lykfb227t2d.png)
LHS = RHS
As the left hand side of the equation is equal to the right hand side of the equation , we have found out the correct value of x .
Therefore , 47 = 2 ( 10 + 3 ) + 3 ( 10 - 3 ) and x = 10 .