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Is (x-2) a factor of f(x)=x^3 -8x^2+14x-4?

1 Answer

14 votes

Answer:

Yes

Explanation:

Use synthetic division

2 | 1 -8 14 -4

____2 -12_4__

1 -6 2 | 0

Thus,
(x^3-8x^2+14x-4)/(x-2)=x^2-6x+2\:\text{R}0, so
(x-2) is indeed a factor of f(x) since there's no remainder.

User Rob Myrick
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