Answer:
s = 51305.88 m
Step-by-step explanation:
Initial velocity of a rocket, u = 25 mph
We need to find the maximum height of the rocket when it reaches its highest point. At this point, the final velocity of the rocket is equal to 0, v = 0
Using the equation of motion,
![v^2-u^2=2as](https://img.qammunity.org/2021/formulas/physics/high-school/62imstr5dn6q95b14ng9iu55jgj34qnto2.png)
Here, a = -g and s is the height reached by rocket
![-u^2=-2gs\\\\s=(u^2)/(2g)\\\\s=((25)^2)/(2* 9.8)\\\\s=31.88\ \text{miles}](https://img.qammunity.org/2021/formulas/physics/high-school/bbgpm630awkdr73mfoeenre3090tka5ntc.png)
We know that, 1 mile = 1609.34 metre
31.88 miles = 51305.88 m
So, the height reached by the rocket is 51305.88 m.