Question

A rocket is launched from the ground with an initial velocity of 25 miles per hour. When the rocket reaches its highest point, it has a velocity of zero for a split second. What is the highest of the rocket in meters when it reaches its highest point?

Answer 1

s = 51305.88 m

Step-by-step explanation:

Initial velocity of a rocket, u = 25 mph

We need to find the maximum height of the rocket when it reaches its highest point. At this point, the final velocity of the rocket is equal to 0, v = 0

Using the equation of motion,

`v^2-u^2=2as`

Here, a = -g and s is the height reached by rocket

`-u^2=-2gs\\\\s=(u^2)/(2g)\\\\s=((25)^2)/(2* 9.8)\\\\s=31.88\ \text{miles}`

We know that, 1 mile = 1609.34 metre

31.88 miles = 51305.88 m

So, the height reached by the rocket is 51305.88 m.