Question

The function f(x)=6x+13 defines a sequence for x≥1. What are the first three terms of the sequence? Item 12 The function f(x)=6x+13 defines a sequence for x≥1. What are the first three terms of the sequence?

Answer 1

The first three terms of the sequence are 19, 25 and 31.

Explanation:

Let
`f(x) = 6\cdot x +13`, which defines a sequence for
`x \geq 1`. This is a case of an arithmetic progression. We obtain the first three terms of the sequence by evaluating the given function at
`x = 1`,
`x = 2` and
`x = 3`, respectively. That is:

x = 1

`f(1) = 6\cdot (1)+13`

`f(1) = 19`

x = 2

`f(2) = 6\cdot (2) +13`

`f(2) = 25`

x = 3

`f(3) = 6\cdot (3) +13`

`f(3) = 31`

The first three terms of the sequence are 19, 25 and 31.