Answer:
27.1feet
Explanation:
Find the diagram attached.
From the diagram:
opposite = AB = 3.8feet
adjacent = BC = x feet
To get the unknown:
tan(theta) = opposite/adjacent
tan(theta) = AB/BC
tan8° = 3.8/BC
BC = 3.8/tan8°
BC = 3.8/0.1405
BC = 27.05 feet
Hence distance of the wall from the ramp is 27.1 feet to the nearest tenth of a foot