Question

If the perimeter of a pool is 102ft, and the length is 6 more than twice the width, what are the dimensions?

Answer 1

Answer:

Length = 36 ft
Width = 15 ft

Explanation:

Let length of pool be ‘x’ ft
Let width of pool be ‘y’ ft
Perimeter = 2(x + y) = 102 ft

By Given:

2(x + y) = 102
=> 2x + 2y = 102 (Eq. 1)

=> x = 2y + 6 (Eq. 2)

Substitute value of ‘x’ from Eq. 2 in 1 :-

2x + 2y = 102
2(2y + 6) + 2y = 102
4y + 12 + 2y = 102
6y + 12 = 102
6y = 102 - 12 = 90
=> y = 90/6 = 15

Therefore, y = 15

Substitute value of ‘y’ in Eq. 2 :-

x = 2y + 6
x = 2(15) + 6
x = 30 + 6
=> x = 36

Therefore, x = 36

Verification:

2x + 2y = 102
2(36) + 2(15) = 102
72 + 30 = 102
=> 102 = 102
LHS = RHS

Therefore,
Length (x) = 36 ft
Width (y) = 15 ft