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Write the nuclear equation for the release of a beta particle by 22888Ra

User Sney
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1 Answer

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The nuclear equation :

₈₈Ra²²⁸ ⇒ ₋₁e⁰ + ₈₉Ac²²⁸

Further explanation

Radioactivity is the process of unstable isotopes to stable isotopes by decay, by emitting certain particles,

  • alpha α particles ₂He⁴
  • beta β ₋₁e⁰ particles
  • gamma particles ₀γ⁰
  • positron particles ₁e⁰
  • neutron ₀n¹

The sum of the mass number and atomic number before and after decay is the same

Ra = Radium ⇒alkaline earth, group 2, block s, period 7

Atomic mass = 88

If an element releases an β ₋₁e⁰, the atomic number of the new element increases by 1

The new element will have an atomic number: 88+1=89 and mass number 288

The element having the atomic number 89 is Actinium(Ac)

So the nuclear equation :

₈₈Ra²²⁸ ⇒ ₋₁e⁰ + ₈₉Ac²²⁸

User RogueDeus
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