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If an emitter current is changed by 4 mA, the collector current changes by 3.5 mA. The value of beta will be :​

User Martin Fabik
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1 Answer

12 votes
12 votes

Given -:

change in emitter current, ∆l(E) = 4 mA

change in collector current,∆I(C) = 3.5 mA

To find -:

value of B

Solution :-

∆I(E) = ∆I(C) + ∆l(B), here ∆l(B) is the change in base current.

4 = 3.5 + ∆l(B)

∆I(B) = 0.5 mA

Now, B = ∆l (C) ÷ ∆l (B)

B = 3.5 ÷ 0.5

B = 7.0

so, the value of A = 7.0

User Docsteer
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