Question

2.70 L of a gas has a pressure of 0.63 atm. What is the volume of the gas at 105kPa?

Answer 1

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4.44l

Step-by-step explanation:

`\sf Volume \: of \: gas \: before(V_1) = 2.7 \: l \\ \sf Pressure \: of \: gas \: before(P_1) = 0.63 \: atm \\ \sf 0.63 * 101.3 = 63.8 \: kPa \\ \sf Volume \: of \: gas \: after(V_2) = ? \\ \sf Pressure \: of \: gas \: after( P_2) = 105 \: kPa`

`\textsf{ By using Boyle's law} \\ \\ \tt{ (P_1)/(V_1) = (P_2)/(V_2) }`

`\sf \longrightarrow (2.70)/(63.8) = (V_2)/(105) \\ \\ \\ \sf \longrightarrow (2.7 * 105)/(63.8) = V_2 \\ \\ \\ \sf \longrightarrow (283.5)/(63.8) = V_2 \\ \\ \\ {\orange {\boxed{ \longrightarrow 4.44 \: l = V_2}}}`