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A 4.2 kg object  compresses a horizontal spring by 5.5 m  beyond its natural length. with a force constant of 570 N/m. it travels down a hill to wards another hill with the speed of 64.07 m/s. How high
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A 4.2 kg object  compresses a horizontal spring by 5.5 m  beyond its natural length. with a force constant of 570 N/m. it travels down a hill to wards another hill with the speed of 64.07 m/s. How high will the object reach?

209.44 m

290.m

306 m

299 m

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User Vaneik
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1 Answer

13 votes

PE=KE

mgh=1/2kx²

4.2 x 9.8 x h = 1/2 x 570 x (5.5)²

h = 209.45 m

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