Question

Two different cylinders have the same

volume. Cylinder 1 has a radius of 3 feet
and a height of 24 feet. Cylinder 2 has a
radius of 6 feet. What is the height of
Cylinder 2?
3

Answer 1

The answer to your question is 6 feet.

hope this helps

Answer 2

Given:

Two different cylinders have the same volume.

To find:

The height of the cylinder 2

Solution:

Volume of the cylinder 1:

`v = \pi {r}^(2) h`

`v = \pi * {3}^(2) * 24`

`v = 678.58401 \: {ft}^(3)`

`v = 678.58 \: {ft}^(3) (2 \: d.p)`

Height of the cylinder 2:

`h = \frac{v}{\pi {r}^(2) }`

`h = \frac{687.58}{\pi * {6}^(2) }`

`h= 5 .99996 \: ft`

`\huge\boxed{\sf{h=6 \: ft}}`

Hence, the height of the cylinder 2 is 6 feet.