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Suppose m∠3 = 128 and m∠6 = (10x + 8). What value of x would result in a || b?

A. 8.2
B. 4.4
C. 17.2
D. 12.0

User Zysaaa
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1 Answer

6 votes

Answer:

x = 12

Explanation:

The attached figure shows the measures of the angles. Here, line a is parallel to line b.

Given that,

m∠3 = 128 and m∠6 = (10x + 8)

We need to find the value of x.

Here,


\angle 3 =\angle 6 (alternate interior angles)

So,


10x+8=128\\\\10x=128-8\\\\10x=120\\\\x=12

So, the value of x is 12. Hence, the correct option is (D).

Suppose m∠3 = 128 and m∠6 = (10x + 8). What value of x would result in a || b? A. 8.2 B-example-1
User Rolands Bondars
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6.9k points