Question

What is the probability that you would land on a R and then a P?

Answer 1

`(1)/(26) * (1)/(26) = (1)/(676) = .00148.`

Explanation:

Multiply the probability of P by the probability of Q.

In which the probability of P is equal to
`(R)/(Total NumberOf LettersInAlphabet) = (1)/(26)`

In which the probability of Q is equal to
`(P)/(Total NumberOf LettersInAlphabet) = (1)/(26)`

There's a 1 in 676 chance that you'd randomly pick R, put the tile back in, and then pick P in a sack of 26 letters of the latin alphabet.

Answer 2

multiply the probability of the first event by the second.

Explanation:

Use the specific multiplication rule formula. Just multiply the probability of the first event by the second. For example, if the probability of event A is 2/9 and the probability of event B is 3/9 then the probability of both events happening at the same time is (2/9)*(3/9) = 6/81 = 2/27.