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A student determines that the density of lead is 10.8g/cm^3. The accepted value for the density of lead is 11.4g/cm^3. What is the error in this student’s measurement?

User UmutKa
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1 Answer

4 votes

Answer:

The answer is 5.26 %

Step-by-step explanation:

The percentage error of a certain measurement can be found by using the formula


P(\%) = (error)/(actual \: \: number) * 100\% \\

actual density = 11.4g/cm³

error = 11.4 - 10.8 = 0.6

We have


p(\%) = (0.6)/(11.4) * 100 \\ = 5.263157894...

We have the final answer as

5.26 %

Hope this helps you

User CoolMcGrrr
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