Question

A 1000-turn toroidal solenoid has a central radius of 4.2 cm and is carrying a current of 1.7 A. What is the magnitude of the magnetic field inside the solenoid at the central radius

Answer 1

The value is
`B  =  0.008095 \ T`

Step-by-step explanation:

From the question we are told that

The number of turn is N = 1000 turns

The radius is
`r =  4.2 \  cm =  0.042 \  m`

The current is
`I  =  1.7 \  A`

Generally the magnetic field is mathematically represented as

`B  =  (\mu_o  *  N *  I  )/(2 \pi r )`

Here
`\mu _o` is the permeability of free space with value

`\mu _o =   4\pi * 10^(-7) N/A^2`

So

`B  =  (4\pi * 10^(-7)  *  1000 *  1.7 )/(2* 3.142 * 0.042 )`

=>
`B  =  0.008095 \ T`