Answer:
Area of the polygon = 46 square units
Explanation:
Irregular polygon is in a composite figure having triangle A, rectangle B and rectangle C.
Area of the polygon = Area of triangle A + Area of rectangle B + area of rectangle C
Area of triangle A =
![(1)/(2)(\text{Base})(\text{Height})](https://img.qammunity.org/2021/formulas/mathematics/college/vjntho5hrd73rxm3zv5ey9l2ej5v944f30.png)
=
= 8 square units
Area of rectangle B = Length × Width
= 8 × 4
= 32 square units
Area of rectangle C = 3 × 2
= 6 square units
Area of the polygon = 8 + 32 + 6
= 46 square units