Question

An eraser is thrown into the air with an initial velocity of 6.2 meters per second.

1. What is its maximum height?

2. How long does it take for you to catch it?

Answer 1

Maximum height = 1.96 (Approc)

Total time = 1.26 second

Step-by-step explanation:

Given:

Final velocity v = 6.2 m/s

Find:

Maximum height

Total time

Computation:

v² = u² + 2as

6.2² = 2(9.8)s

S = 1.96 m Approx

Maximum height = 1.96 (Approc)

v = u + at

6.2 = (9.8)(t)

Total time = 0.63 x 2

Total time = 1.26 second