Question

The observed rotation of a solution of 1.3 g of a compound in 10 mL of water is 11 degrees. If the pathlength is 10 cm, what is the specific rotation of the compound

Answer 1

The specific rotation of the compound is +84.6°.

Step-by-step explanation:

The specific rotation of the compound can be found using the following equation:

`[\alpha] = (\alpha)/(c*l)`

Where:

α: is the observed rotation of a solution = +11°

c: is the concentration

l: is the pathlength = 10 cm = 1.0 dm

`[\alpha] = (\alpha)/(c*l) = (+11)/((1.3 g)/(10 mL)*1.0 dm) = +84.6 ^(\circ)`

Therefore, the specific rotation of the compound is +84.6°

I hope it helps you!