Question

Which steps can be used to verify that tan(w + Pi) = tan(w)?

Answer 1

D. Rewrite tan(w + Pi) using the tangent sum identity. Then simplify the resulting expression using tan(Pi) = 0.

Explanation:

test on edge

Answer 2

D. proves
`tan(w + \pi) = tanw`

Explanation:

Given

`tan(w + \pi) = tan(w)`

See attachment for complete question

Option D answers the question (See proof below).

Using tangent sum identity, we have:

`tan(A + B) = (tanA + tanB)/(1 - tanAtanB)`

In this case:

`A = w`

`B = \pi`

So, we have:

`tan(w + \pi) = (tanw + tan \pi)/(1 - tanw. tan \pi)`

Note that

`tan\ pi = 0`

So:

`tan(w + \pi) = (tanw + tan \pi)/(1 - tanw. tan \pi)`

`tan(w + \pi) = (tanw + 0)/(1 - tanw * 0)`

`tan(w + \pi) = (tanw)/(1)`

`tan(w + \pi) = tanw`

Hence: Option D answers the question