Answer:
0.22663
Explanation:
Given that:
N(30, 8)
Normal distribution :
Mean(m) = 30
Standard deviation (s) = 8
X = 36
To run out of pastries then demand is greater than 36
Zscore = (X - m) / s
Zscore = (36 - 30) / 8
Zscore = 0.75
P(Z > 0.75) = 1 - P(Z < 0.75)
P(Z < 0.75) = 0.77337
P(Z > 0.75) = 1 - 0.77337
= 0.22663