Question

In the previous question, what is the current crossing resistor R1 if the current leaving the battery is 5.0A?

Answer 1

Answer: the current crossing resistor R1 if the current leaving the battery is 5.0A is 2.0 Ω

Step-by-step explanation:

In the previous question;

R1 = 15 Ω, R2 = 3.0 Ω, R3 = 7.0 Ω just as shown in the image uploaded along this answer; R2 and R3 are in series

so Rq1 = R2 + R3 = 3 + 7 = 10 Ω

now Rq1 and r1 are in pararell

so,

1/Rq = 1/Rq1 + 1/R1 = 1/10Ω + 1/15Ω

Rq = 6 Ω

Now In the previous question, what is the current crossing resistor R1 if the current leaving the battery is 5.0A?

Rq1 = 3 + 7 = 10 Ω

R1 = 15 Ω

current in R1 = I₁

therefore

I₁ = I(Rq1 / ( R1 + Rq1))

so we substitute

I₁ = 5 × ( 10 / ( 15 + 10))

I₁ = 5 × 10/25

I₁ = 50 / 25

I₁ = 2.0 Ω

so the current crossing resistor R1 if the current leaving the battery is 5.0A is 2.0 Ω