Question

By pipet, 5.00 mL of a 0.823 M stock solution of potassium permanganate (KMnO4) was transferred to a 50.00-mL volumetric flask and diluted to the calibration mark. Determine the molarity of the resulting solution.

Answer 1

0.0823 M

Step-by-step explanation:

To solve this problem we can use the formula:

• C₁V₁=C₂V₂

Where

C₁ = 0.823 M

V₁ = 5.00 mL

C₂ = ?

V₂ = 50.00 mL

So now it's just a matter of calculating C₂:

• 0.823 M * 5.00 mL = C₂ * 50.00 mL

C₂ = 0.0823 M

The molarity of the resulting solution is 0.0823 M.