Question

How many joules are absorbed when 50.0 g of water are heated from 30.2 deg.
C to 58.6 deg. C?

Answer 1

`Q=5941.3J`

Step-by-step explanation:

Hello.

In this case, since the water is absorbing heat because its temperature raises from 30.2 °C to 58.6 °C, we can compute the amount of heat shown below:

`Q=mCp\Delta T`

Whereas the specific heat of water is known to 4.184 J/(g°C), thus, we obtain:

`Q=50.0g*4.184(J)/(g\°C)(58.6-30.2)\°C \\\\Q=5941.3J`

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