9.5k views
3 votes
Find the sample variance and standard deviation. ​, ​, ​, ​, ​, ​, ​, ​, ​, Choose the correct answer below. Fill in the answer box to complete your choice. ​(Round to two decimal places as​ needed.)

User Joliejuly
by
5.7k points

1 Answer

1 vote

This question is incomplete, the complete question is;

Find the sample variance and standard deviation.

7​, 55​, 14​, 49​, 32​, 23​, 30​, 32​, 34​,27

Choose the correct answer below. Fill in the answer box to complete your choice. ​(Round to two decimal places as​ needed.)

Answer:

Sample Variance S² = 205.79

Sample standard deviation S = 14.35

Explanation:

Given that;

the observation are; 7​, 55​, 14​, 49​, 32​, 23​, 30​, 32​, 34​,27

First we calculate Sample Mean

⁻x = (∑xi) / n

⁻x = ( 7​ + 55​ + 14​ + 49​ + 32​ + 23​ + 30​ + 32​ + 34​ + 27 ) / 10

⁻x = 303 / 10 = 30.3

mean ⁻x = 30.3

now to calculate Sample variance;

Sample Variance S² = (∑(xi - ⁻x )²) / (n-1)

⁻x is sample mean

xi is element in the sample

n is sample size

so

Xi (xi - ⁻x ) (xi - ⁻x )²

7​ -23.3 542.89

55​ 24.7 610.09

14​ -16.3 265.69

49​ 18.7 349.69

32​ 1.7 2.89

23​ -7.3 53.29

30​ -0.3 0.09

32​ 1.7 2.89

34​ 3.7 13.69

27 -3.3 10.89

TOTAL ∑ 1852.1

Sample Variance S² = (∑(xi - ⁻x )²) / (n-1)

So we substitute

Sample Variance S² = 1852.1 / ( 10 - 1)

Sample Variance S² = 1852.1 / 9

Sample Variance S² = 205.79

Sample standard deviation S = √ [ (∑(xi - ⁻x )²) / (n-1)]

i.e Sample standard deviation S = √ ( Sample Variance )

Sample standard deviation S = √ 205.79

Sample standard deviation S = 14.35

User EarlyPoster
by
5.2k points