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ron-59 is a beta emitter with a half-life of 44.5 days. If a sample initially contains 144 mg of iron-59, how much iron-59 is left in the sample after 213 days?

1 Answer

5 votes

Answer:

5.22 mg

Step-by-step explanation:

Half life is the amount of time taken for a substance to reduce to half of its initial value. The half life is calculated using:


N=N_0((1)/(2) )^{(t)/(t_(1/2)) }\\\\N_0=initial\ amount\ of\ substance,N=final\ amount\ of\ substance,t_(1/2)=half-life, t=time\ elapsed\\\\Given\ that\ N_0=144mg, t=213\ days,t_(1/2)=44.5\ days\\\\N=N_0((1)/(2) )^{(t)/(t_(1/2)) }\\\\N=144\ mg*((1)/(2) )^{(213\ days)/(44.5\ days) }\\\\N=5.22\ mg

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