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3 votes
2. Write an equation that is perpendicular to y = -x +2 and goes
through the point (-3, 1).

2 Answers

2 votes

Answer:

x - y + 4 =0

Explanation:

y = -x +2 => x + y - 2 = 0

suppose: (d') ⊥ (d) ; (d): x + y - 2 =0


(d'): \left \{ {goes through A(-3;1)} \atop {(d') perpendicular to (d): x+y-2 = 0 }} \right\\.

=> (d'): x - y + 4 =0

User BriteSponge
by
8.4k points
2 votes

Answer:x1-x2 - y1-y2

Explanation:

User Kevin ABRIOUX
by
8.2k points

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