Question

An archer shoots a 150. gram arrow straight up in the air. (Do not try this at home.) The bow was drawn back 75.0 cm by a 175 N force. How high does the arrow rise assuming air friction is negligible

Answer 1

The arrow rise 44.64 m high assuming air friction is negligible

Step-by-step explanation:

According to the law of conservation of energy

Kinetic energy = Potential energy at highest

`(1)/(2)kx^2=mgh`----1

We know that F=kx

So,
`k = (F)/(x)\\k=(175)/(0.75)`

Substitute the value in 1

`(1)/(2)((175)/(0.75))(0.75)^2=0.15 * 9.8 * h\\((1)/(2)((175)/(0.75))(0.75)^2)/(0.15 * 9.8)=h\\44.64 = h`

Hence the arrow rise 44.64 m high assuming air friction is negligible