Question

Compute the kinetic energy of a proton (mass 1.67×10−27kg ) using both the nonrelativistic and relativistic expressions for speed of 6.00×107m/s.

Answer 1

`KE = 5.01 * 10^(-13)Joules`

Step-by-step explanation:

Kinetic energy is the energy possessed by a body by virtue of its motion. It is expressed as;

`KE = (1)/(2)mv^2\\` where:

m is the mass of proton

v is the speed

Substitute:

`KE = (1)/(2)(1.67* 10 ^(-27))(6.0*10^7)^2\\\\KE = (1)/(2)(1.67* 10 ^(-27))(6.0*10^(14))\\\\\\KE = (1)/(2)(1.67* 6.0 * 10 ^(-27)*10^(14))\\\\KE = (1)/(2)(1.67* 6.0 * 10 ^(-27+14))\\\\KE = 3 * 1.67 * 10^(-13)\\\\KE = 5.01 * 10^(-13)Joules`

Hence the kinetic energy of a proton is
`5.01 * 10^(-13)Joules`