Question

A solenoid used to produce magnetic fields for research purposes is 1.6 m long, with an inner radius of 30 cm and 1200 turns of wire. When running, the solenoid produced a field of 1.2 T in the center. How large a current does this carry

Answer 1

1273.07 A

Step-by-step explanation:

Using,

B = μI(N/L).................... Equation 1

Where B = Magnetic field, μ = permiability of thr core, I = current, N = Number of turns, L = Length.

Making I the subject of the equation above,

I = BL/Nμ.................. Equation 2

Given: B = 1.2 T, L = 1.6 m, N = 1200 turns

Constant: μ = 4π×10⁻⁷T.A/m

Substitute these values into equation 2

I = 1.2(1.6)/( 4π×10⁻⁷×1200)

I = 1.92×10⁷/(4π×1200)

I = 19200000/15081.6

I = 1273.07 A

Hence it carries a current of 1273.07 A