Question

For a huge luxury liner to move with constant velocity, its engines need to supply a forward thrust of 6.85 105 N. What is the magnitude of the resistive force exerted by the water (in N) on the cruise ship?

Answer 1

The magnitude of the resistive force exerted by the water is
`6.85* 10^(5)` newtons.

Step-by-step explanation:

By First and Second Newton's Law, the resistive force exerted by the water on the cruise ship has the same magnitude of forward thrust, with which it is antiparallel to. The equation of equilibrium for the luxury liner is:

`\Sigma F = F-R = 0` (Eq. 1)

Where:

`F` - Forward trust, measured in newtons.

`R` - Resistive force exerted by the water, measured in newtons.

From (Eq. 1), we get that: (
`F = 6.85* 10^(5)\,N`)

`R = F`

`R = 6.85* 10^(5)\,N`

The magnitude of the resistive force exerted by the water is
`6.85* 10^(5)` newtons.